The probability of our event occurring is .8.
We construct a binomial distribution, with 4 trials, of which we want 3 to occur.
B(4, .8)
P(3) = .4096
a rifleman averages 8 hits out of 10 shots at a tare what is the probability that he will hit the target 3 out of 4 shots 4c3*(.8)*(.2)
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