From d = Vo^2[sin(2µ)]/g
91.4 = 328^2[sin(2µ)]/9.8, µ = .2385º or 89.7615º.
a rifle that has been ‘sighted in' for a 91.4-meter target. If the muzzle speed of the bullet is v0 = 328 m/s, there are the two possible angles è1 and è2 between the rifle barrel and the horizontal such that the bullet will hit the target. One of these angles is so large that it is never used in target shooting. Give your answers as (a) the smaller angle and (b) the larger angle.
3 answers
what would be the smaller angle because 89.76 is the larger angle
do you just subtract from 90 to get the other angle
1 answer