how long does it take (t) for gravity to drop the bullet?
1/2 * 980 cm/s^2 * t^2 = 1.9 cm ... solve for t
(b) the target distance divided by the flight time gives the AVERAGE velocity
... should be close to the muzzle velocity, but not the same
A rifle is aimed horizontally at a target 30m away. The bullet hits the target 1.9 cm below
the aiming point. (a) What is the bullet’s time of flight? (b) What is the muzzle velocity?
2 answers
a) y=-1/2 gt^2
so, t=root((-2)*(-0.019m)/9.8m/s^2)=6.2x10^-2s
b)Muzzle velocity =x/t=30m/6.2x10^-2s=4.8x10^-2 m/s
so, t=root((-2)*(-0.019m)/9.8m/s^2)=6.2x10^-2s
b)Muzzle velocity =x/t=30m/6.2x10^-2s=4.8x10^-2 m/s