A resultant force of 20 N gives a body of mass m an acceleration of 8 m/s^2 and a body of mass m' acceleration of 24 m/s^2. What acceleration will this force cause the two masses to acquire if fastened together.

Question

Ruel VT · Accepted Answer

F = 20N A1 = 8 m/s^2 A2 = 24 m/s^2 F = ma M1 = F/A1 M1 = 20N/8 m/s^2 M1 = 2.25 kg F = ma M2 = F/A2 M2 = 20N/ 24 m/s^2 M2 = 0.83 kg M1 + M2 = 3.33 kg a = F/M a = 20N / 3.33 kg a = 6.01 m/s^2

Ruel VT · Answer

F = 20N A1 = 8 m/s^2 A2 = 24 m/s^2 F = ma M1 = F/A1 M1 = 20N/8 m/s^2 M1 = 2.50 kg F = ma M2 = F/A2 M2 = 20N/ 24 m/s^2 M2 = 0.83 kg M1 + M2 = 3.33 kg a = F/M a = 20N / 3.33 kg a = 6.01 m/s^2

DAVID · Answer

Correct 👍👍

Karan Jack · Answer

F=20N
a1=8m/s^2
a2=24m/s^2
Let mass in first case be m1,
and mass in second case be m2.
1st case,
F=m1a2
m1=F/a1
=20/8
=5/2
2nd case,
F=m2a2
m2=F/a2
=20/24
=5/6
Total mass=m1+m2
=5/2 + 5/6
=10/3
a=F/total mass
=20/10/3
=20×3/10
=60/10
=6m/s^2.