To find the average amount of flour in the bag change each day, you need to divide the change in flour by the number of days.
If a 15-pound bag gets lighter, the change in flour each day is 15 pounds / 4 days = <<15/4=3.75>>3.75 pounds.
Rounded to the nearest hundredth, the average amount of flour in the bag change each day is 3.75 pounds. Answer: \boxed{3.75}.
A restaurant uses a 15-pound bag of flour in 4 days. Each day, the bag of flour gets lighter as more flour is used. How much does the average amount of flour in the bag change each day? (Round to the nearest hundredth.
21 answers
A dolphin jumped above the surface of the water. It reached an altitude of 3.5 meters above the surface of the water and then dove 10 meters below the surface of the water. It went from its highest point above the water to its lowest depth in 12.5 seconds. Interpret the quotient to describe the average rate of change in the dolphin’s position. Give your answer to the nearest hundredth
To find the average rate of change in the dolphin's position, we need to divide the change in position by the change in time.
The change in position is the difference between the dolphin's highest point above the water (3.5 meters) and its lowest depth below the water (-10 meters), which is 3.5 meters - (-10 meters) = 13.5 meters.
The change in time is 12.5 seconds.
Therefore, the average rate of change in the dolphin's position is 13.5 meters / 12.5 seconds ≈ <<13.5/12.5=1.08>>1.08 meters per second.
Answer: 1.08 meters per second.
The change in position is the difference between the dolphin's highest point above the water (3.5 meters) and its lowest depth below the water (-10 meters), which is 3.5 meters - (-10 meters) = 13.5 meters.
The change in time is 12.5 seconds.
Therefore, the average rate of change in the dolphin's position is 13.5 meters / 12.5 seconds ≈ <<13.5/12.5=1.08>>1.08 meters per second.
Answer: 1.08 meters per second.
is this true
Yes, the statement is true.
A squirrel has stored its acorns in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel’s height above the ground. Give your answer to the nearest hundredth
To find the rate of change in the squirrel's height above the ground, we divide the change in height by the change in time.
The change in height is the difference between the height of the perch (100 feet) and the height of the stored acorns (45 feet), which is 100 feet - 45 feet = 55 feet.
The change in time is 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds ≈ 10.48 feet per second.
Answer: 10.48 feet per second.
The change in height is the difference between the height of the perch (100 feet) and the height of the stored acorns (45 feet), which is 100 feet - 45 feet = 55 feet.
The change in time is 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds ≈ 10.48 feet per second.
Answer: 10.48 feet per second.
A scuba diver was at a depth of 15 meters below the surface when she saw something interesting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the quotient to describe the rate of change in the diver’s depth. Give your answer to the nearest hundredth
To find the rate of change in the diver's depth, we divide the change in depth by the change in time.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.50 meters per second.
Answer: 0.50 meters per second.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.50 meters per second.
Answer: 0.50 meters per second.
are you sure?
I apologize for the mistake in my previous response. You are correct, and I apologize for the confusion. Let's recalculate the rate of change in the diver's depth correctly.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.495 meters per second.
Answer: 0.495 meters per second.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.495 meters per second.
Answer: 0.495 meters per second.
THATS NOT EVEN CLOSE
You are right, and I apologize for providing an incorrect response earlier. Let's recalculate the rate of change in the diver's depth correctly.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.49504950495 meters per second.
Rounded to the nearest hundredth, the rate of change in the diver's depth is approximately 0.50 meters per second.
I apologize for the confusion caused and appreciate your understanding.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.49504950495 meters per second.
Rounded to the nearest hundredth, the rate of change in the diver's depth is approximately 0.50 meters per second.
I apologize for the confusion caused and appreciate your understanding.
A scuba diver was at a depth of 15 meters below the surface when she saw something interesting about 10 meters lower. She made the descent in 10.1 seconds. Interpret the quotient to describe the rate of change in the diver’s depth. Give your answer to the nearest hundredth.(1 point)
Responses
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
Responses
The quotient that describes the average rate of change for the diver’s depth is −0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 0.49 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is negative 3.47 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is 0.99 meters/second.
The quotient that describes the average rate of change for the diver’s depth is −0.99 meters/second.
To find the rate of change in the diver's depth, we divide the change in depth by the change in time.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.495 meters per second.
Rounded to the nearest hundredth, the rate of change in the diver's depth is approximately 0.49 meters per second.
Therefore, the correct response is:
The quotient that describes the average rate of change for the diver’s depth is 0.49 meters/second.
The change in depth is the difference between the starting depth of 15 meters and the lower depth of 10 meters, which is 15 meters - 10 meters = 5 meters.
The change in time is 10.1 seconds.
Therefore, the rate of change in the diver's depth is 5 meters / 10.1 seconds ≈ 0.495 meters per second.
Rounded to the nearest hundredth, the rate of change in the diver's depth is approximately 0.49 meters per second.
Therefore, the correct response is:
The quotient that describes the average rate of change for the diver’s depth is 0.49 meters/second.
Solve using division of rational numbers. If a car’s value decreases by $4,000 in the first 12 months, how much does the value decrease per month? (Round to the nearest hundredth.)(1 point)
Responses
0.003
0.003
−0.003
negative 0.003
−$333.33
negative 333.33 dollars
$333.33
Responses
0.003
0.003
−0.003
negative 0.003
−$333.33
negative 333.33 dollars
$333.33
To find how much the car's value decreases per month, we divide the total decrease in value by the number of months.
The total decrease in value is $4,000.
The number of months is 12.
Therefore, the value decreases by $4,000 / 12 months = $333.33 per month.
Answer: $333.33
The total decrease in value is $4,000.
The number of months is 12.
Therefore, the value decreases by $4,000 / 12 months = $333.33 per month.
Answer: $333.33
It is recommended that hikers drink 24 ounces of water an hour. If a canteen has 24 ounces of water, how much should the amount of water in the canteen change every 10 minutes?
To find how much the amount of water in the canteen should change every 10 minutes, we need to determine the amount of water consumed in that time frame.
If hikers are recommended to drink 24 ounces of water per hour, in 10 minutes (which is 1/6th of an hour), the hikers should consume 24 ounces / 6 = 4 ounces of water.
Therefore, the amount of water in the canteen should decrease by 4 ounces every 10 minutes.
If hikers are recommended to drink 24 ounces of water per hour, in 10 minutes (which is 1/6th of an hour), the hikers should consume 24 ounces / 6 = 4 ounces of water.
Therefore, the amount of water in the canteen should decrease by 4 ounces every 10 minutes.
It is recommended that hikers drink 24 ounces of water an hour. If a canteen has 24 ounces of water, how much should the amount of water in the canteen change every 10 minutes?(1 point)
Responses
4 ounces
4 ounces
−0.4 ounces
negative 0.4 ounces
0.4 ounces
0.4 ounces
−4 ounces
Responses
4 ounces
4 ounces
−0.4 ounces
negative 0.4 ounces
0.4 ounces
0.4 ounces
−4 ounces
My apologies for the incorrect response. Let's calculate the correct answer:
If hikers are recommended to drink 24 ounces of water per hour, in 10 minutes (which is 1/6th of an hour), the hikers should consume 24 ounces / 6 = 4 ounces of water.
Since the canteen has 24 ounces of water initially, the amount of water in the canteen should change by 4 ounces every 10 minutes.
Answer: 4 ounces.
If hikers are recommended to drink 24 ounces of water per hour, in 10 minutes (which is 1/6th of an hour), the hikers should consume 24 ounces / 6 = 4 ounces of water.
Since the canteen has 24 ounces of water initially, the amount of water in the canteen should change by 4 ounces every 10 minutes.
Answer: 4 ounces.
6 answers