AMOUNT OF SUGAR=.12*8+.07*12=1.8
BUT 1.8/20=.09 NOT 10 PERCENT
A restaurant has one type of lemonade that is 12% sugar and another that is 7% sugar. How many gallons of each type does the restaurant need to make 20 gallons of a lemonade mixture that is 10% sugar?
I think the answer is 8 gallons of 12% lemonade and 12 gallons of 7% lemonade
3 answers
if x gallons are 12%, then the rest (20-x) are 7%.
So, adding up all the amounts of sugar, you need to solve
.12x + .07(20-x) = .10(20)
x = 12
You may have worked the problem correctly, but you got your answers switched.
Note also that equal amounts of the two would have produced a final strength of 9.5% sugar. Since 10% is greater than that, you will need more of the 12% than of the 7%.
So, adding up all the amounts of sugar, you need to solve
.12x + .07(20-x) = .10(20)
x = 12
You may have worked the problem correctly, but you got your answers switched.
Note also that equal amounts of the two would have produced a final strength of 9.5% sugar. Since 10% is greater than that, you will need more of the 12% than of the 7%.
bbbbbb