A resort is building a scuba diving lagoon in the shape of an upside down pyramid. The top of the lagoon is a rectangle that is 50 feet by 20 feet, and the deepest point of the lagoon is in the middle at 25 feet deep. How much water does the lagoon hold?(1 point) Responses 95 ft.3 95 feet cubed 25,000 ft.3 25,000 feet cubed 75,000 ft.3 75,000 feet cubed 8,333.33 ft.3

1 answer

To find the volume of the upside down pyramid-shaped lagoon, we need to calculate the volume of the rectangular top and subtract the volume of the smaller rectangular shape at the bottom.

The volume of a rectangular shape is calculated by multiplying its length, width, and height. In this case, the rectangular top has a length of 50 feet, a width of 20 feet, and a height of 25 feet, as the deepest point is in the middle at 25 feet deep.

Volume of the rectangular top = 50 ft * 20 ft * 25 ft = 25000 ft³

Next, we need to calculate the volume of the smaller rectangular shape at the bottom of the lagoon. Since this shape is in the middle, it has dimensions that are half of the rectangular top. Therefore, the length is 50 ft divided by 2, which is 25 ft, the width is 20 ft divided by 2, which is 10 ft, and the height is 25 ft, same as the deepest point.

Volume of the smaller rectangular shape = 25 ft * 10 ft * 25 ft = 6250 ft³

Finally, we subtract the volume of the smaller rectangular shape from the volume of the rectangular top to find the volume of the lagoon.

Volume of the lagoon = Volume of the rectangular top - Volume of the smaller rectangular shape
Volume of the lagoon = 25000 ft³ - 6250 ft³ = 18750 ft³

Therefore, the lagoon holds 18,750 ft³ of water.