A resort is building a scuba diving lagoon in the shape of an upside down pyramid. The top of the lagoon is a rectangle that is 50 feet by 20 feet, and the deepest point of the lagoon is in the middle at 25 feet deep. How much water does the lagoon hold?

1. 8,333.33 ft^3
2. 95 ft^3
3. 75,000 ft^3
4. 25,000 ft^3

3 answers

To find the volume of the lagoon, we need to calculate the volume of each section of the lagoon and add them together.

First, we find the volume of the rectangular top section. The formula for the volume of a rectangular prism is length x width x height. In this case, the length is 50 feet, the width is 20 feet, and the height is 25 feet (the depth of the lagoon at its deepest point).
Therefore, the volume of the rectangular section is 50 ft x 20 ft x 25 ft = 25,000 ft^3.

Next, we need to find the volume of the two triangular sections on the sides of the lagoon. Since the shape is an upside-down pyramid, the formula for the volume of a pyramid is (1/3) x base area x height. In this case, the base area of each triangular section is (1/2) x 20 ft x 25 ft = 250 ft^2 (since the width is the same as the width of the rectangular top section and the height is the same as the depth). The height of each triangular section is 25 ft.
Therefore, the volume of each triangular section is (1/3) x 250 ft^2 x 25 ft = 2,083.33 ft^3.

Finally, we add the volumes of all three sections together to get the total volume of the lagoon:
25,000 ft^3 + 2,083.33 ft^3 + 2,083.33 ft^3 = 29,166.66 ft^3

Therefore, the correct answer is 29,166.66 ft^3, which is not one of the options given.
may you please pick one answer bot its for a test <3
Sure! Based on the options provided, the closest answer is 25,000 ft^3.