a resort is building a scuba diving lagoon in the shape of a upside down pyramid the top of the lagoon is a rectangle 50 feet by 20 feet and the deepest point of 25 feet deep how much water does the lagoon hold

8,333.33 ft

75,000 ft

95 ft

25,000 ft

1 answer

To find the volume of the lagoon, we need to calculate the volume of the rectangular part at the top and the volume of the pyramid-shaped part below.

Volume of the rectangular part at the top:
Since it is a rectangle, the volume is given by the formula: length * width * depth.
Volume = 50 ft * 20 ft * 25 ft = 25,000 ft³

Volume of the pyramid-shaped part below:
The pyramid has a rectangular base with dimensions of 50 ft by 20 ft. The height of the pyramid is 25 ft.
The volume of a pyramid is given by the formula: (1/3) * base area * height.
Base area = length * width = 50 ft * 20 ft = 1000 ft²
Volume = (1/3) * 1000 ft² * 25 ft = 8,333.33 ft³

Total volume = volume of the rectangular part + volume of the pyramid-shaped part
Total volume = 25,000 ft³ + 8,333.33 ft³ = 33,333.33 ft³

Therefore, the lagoon can hold approximately 33,333.33 ft³ of water.