To determine the power dissipated in the circuit, we need to calculate the total resistance of the circuit first.
The equivalent resistance of the parallel combination is given by:
1/R_total = 1/R + 1/15
Solving for R, we get:
1/R_total = 1/R + 1/15
1/R_total = (15+R)/(15R)
R_total = 15R/(15+R)
The total resistance of the circuit is then:
R_total = 15R/(15+R) + 30
Now, we can calculate the current flowing through the circuit using Ohm's Law:
I = V/R_total
= 160 / (15R/(15+R) + 30)
Finally, we can calculate the power dissipated in the circuit using the formula:
P = I^2 * R_total
Substitute the expressions for I and R_total into the equation to find the power dissipated.
a resistor of unknown value R is connected in parallel with a resistance of 15 ohms.this combination is connected in series with a resistance of 30 ohms.the current is then connected across a 160v DC supply. determine the power dissipated in the circuit
1 answer
1 answer