q = Ccal x delta T
(Ccal is heat capacity of the calorimeter 28.90 kJ/K and delta T = 2.77 C).
Solve for q = heat produced by 4.30 g of the candy in kJ.
Convert that J (multiply by 1000).
Convert that to calories (divide by 4.184).
Convert that to nutritional calories (divide by 1000) which gives you calories for the 4.30 g piece of candy.
Divide by 4.30 to convert to nutritional calories/grams candy.
A researcher studying the nutritional value of a new candy places a 4.30-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.77 °C. If the heat capacity of the calorimeter is 28.90 kJ·K–1, how many nutritional Calories are there per gram of the candy?
Please help, I don't know how to start!
4 answers
Thank you so much!
Is K kalvin? If so, why isn't celcius converted?
Kelvin*