just a guess - the real chemists can answer with certainty, but the numbes and units suggest
2.53°C * 34.4 kJ/°C = 87.032 kJ
because °C = °K in this context.
Now, don't you have a conversion factor for kJ to calories?
A researcher studying the nutritional value of a new candy places a 5.90g
sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.53 degrees Celsius. If the heat capacity of the calorimeter is 34.40 kJ⋅K^-1, how many nutritional calories are there per gram of the candy?
2 answers
To follow up on oobleck.
You have 87.032 kJ. That converts to 87.032 kJ x (1000 J/kJ) x (1 cal/4.184 J) = what the nutritionists call a "small calorie". Divide by 1000 to convert to what the nutritionists call "big or large calorie). You can see that the calories we think we are eating actually are big calories; i.e., a cup of milk is listed on all of the charts as about 160 calories but that actually is 160 kcal.
You have 87.032 kJ. That converts to 87.032 kJ x (1000 J/kJ) x (1 cal/4.184 J) = what the nutritionists call a "small calorie". Divide by 1000 to convert to what the nutritionists call "big or large calorie). You can see that the calories we think we are eating actually are big calories; i.e., a cup of milk is listed on all of the charts as about 160 calories but that actually is 160 kcal.
1 answer