A researcher is cooling a metal. She cools the metal so that the temperature of the metal drops at a constant rate. After minutes of cooling, the metal is . After minutes, the metal is .
(a)Choose the statement that best describes how the time and the temperature of the metal are related. Then fill in the blank.
As time increases, the temperature of the metal decreases.
The temperature of the metal decreases at a rate of °C per minute.
As time increases, the temperature of the metal increases.
The temperature of the metal increases at a rate of °C per minute.
(b)What was the temperature of the metal when the researcher started cooling it?
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(b) The temperature of the metal when the researcher started cooling it is not provided in the given information.
A researcher is cooling a metal. She cools the metal so that the temperature of the metal drops at a constant rate. After 19 minutes of cooling, the metal is 401°C. After 42 minutes, the metal is 148°C.
(a)Choose the statement that best describes how the time and the temperature of the metal are related. Then fill in the blank.
As time increases, the temperature of the metal decreases.
The temperature of the metal decreases at a rate of °C per minute.
As time increases, the temperature of the metal increases.
The temperature of the metal increases at a rate of °C per minute.
(b)What was the temperature of the metal when the researcher started cooling it?
(a)Choose the statement that best describes how the time and the temperature of the metal are related. Then fill in the blank.
As time increases, the temperature of the metal decreases.
The temperature of the metal decreases at a rate of °C per minute.
As time increases, the temperature of the metal increases.
The temperature of the metal increases at a rate of °C per minute.
(b)What was the temperature of the metal when the researcher started cooling it?
(a) As time increases, the temperature of the metal decreases.
The temperature of the metal decreases at a rate of 7.84°C per minute.
(b) To find the temperature of the metal when the researcher started cooling it, we can use the rate of temperature decrease to extrapolate backwards. Assuming the rate of decrease is constant, we can calculate the temperature at the beginning of cooling as follows:
Rate of temperature decrease = (final temperature - initial temperature) / (final time - initial time)
Substituting the given values:
7.84 = (148 - initial temperature) / (42 - 19)
Solving for the initial temperature:
7.84 * (42 - 19) = 148 - initial temperature
239.36 = 148 - initial temperature
initial temperature = 148 - 239.36
initial temperature ≈ -91.36°C
Therefore, the temperature of the metal when the researcher started cooling it was approximately -91.36°C.
The temperature of the metal decreases at a rate of 7.84°C per minute.
(b) To find the temperature of the metal when the researcher started cooling it, we can use the rate of temperature decrease to extrapolate backwards. Assuming the rate of decrease is constant, we can calculate the temperature at the beginning of cooling as follows:
Rate of temperature decrease = (final temperature - initial temperature) / (final time - initial time)
Substituting the given values:
7.84 = (148 - initial temperature) / (42 - 19)
Solving for the initial temperature:
7.84 * (42 - 19) = 148 - initial temperature
239.36 = 148 - initial temperature
initial temperature = 148 - 239.36
initial temperature ≈ -91.36°C
Therefore, the temperature of the metal when the researcher started cooling it was approximately -91.36°C.
U sure
Apologies, I made an error in my calculation. Let's go through the calculation again correctly:
Rate of temperature decrease = (final temperature - initial temperature) / (final time - initial time)
Substituting the given values:
7.84 = (148 - initial temperature) / (42 - 19)
Solving for the initial temperature:
7.84 * (42 - 19) = 148 - initial temperature
7.84 * 23 = 148 - initial temperature
180.32 = 148 - initial temperature
initial temperature = 148 - 180.32
initial temperature ≈ -32.32°C
Therefore, the temperature of the metal when the researcher started cooling it was approximately -32.32°C.
Rate of temperature decrease = (final temperature - initial temperature) / (final time - initial time)
Substituting the given values:
7.84 = (148 - initial temperature) / (42 - 19)
Solving for the initial temperature:
7.84 * (42 - 19) = 148 - initial temperature
7.84 * 23 = 148 - initial temperature
180.32 = 148 - initial temperature
initial temperature = 148 - 180.32
initial temperature ≈ -32.32°C
Therefore, the temperature of the metal when the researcher started cooling it was approximately -32.32°C.
3 answers