In this scenario, we can use the formula for calculating the minimum sample size:
n = (Z^2 * σ^2) / E^2
Where:
n = sample size
Z = z-score corresponding to the desired confidence level (0.85 for 85% confidence interval)
σ = standard deviation (1.1 pounds)
E = maximum error (0.08 pounds)
Substitute the values:
n = (1.4401 * 1.21) / 0.0064
n ≈ 272.7285
Since we can't have a fraction of a person in a sample, we must round up to the next higher whole number.
Therefore, the minimum number of people over age 43 that must be included in their sample is 273.
A research company desires to know the mean consumption of meat per week among people over age 43
. They believe that the meat consumption has a mean of 2.7
pounds, and want to construct a 85%
confidence interval with a maximum error of 0.08
pounds. Assuming a standard deviation of 1.1
pounds, what is the minimum number of people over age 43
they must include in their sample? Round your answer up to the next integer.
1 answer