A rescue helicopter lifts a 65 kg person straight up by means of a cable. The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 13 m.

Question

A rescue helicopter lifts a 65 kg person straight up by means of a cable. The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 13 m. 
(a) What is the tension in the cable?
 N
(b) How much work is done by the tension in the cable?
 J
(c) How much work is done by the person's weight?
 J
(d) Use the work-energy theorem and find the final speed of the person.
 m/s

bobpursley · Answer

The tension is mg+ma The work done by tension is tension*13 work done by weigh? mg*13 worktension=changePE+KEchange solve for KE change, then velocity from that.

Brandon · Answer

How do you solve for KE change? Work done by weight- 65*9.8*13= 8281 right?