To find which points would appear on the graph of the linear function \( C = 1.25m + 25 \), we can calculate \( C \) (the total cost) for various values of \( m \) (the miles driven).
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For \( m = 2 \): \[ C = 1.25(2) + 25 = 2.5 + 25 = 27.5 \] So, the point is \( (2, 27.5) \).
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For \( m = 4 \): \[ C = 1.25(4) + 25 = 5 + 25 = 30 \] So, the point is \( (4, 30) \).
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For \( m = 30 \): \[ C = 1.25(30) + 25 = 37.5 + 25 = 62.5 \] So, the point is \( (30, 62.5) \).
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For \( m = 35 \): \[ C = 1.25(35) + 25 = 43.75 + 25 = 68.75 \] So, the point is \( (35, 68.75) \).
Now let's check the options:
A: \( (2, 22.5) \) and \( (4, 20) \) — Neither of these points are correct since we calculated \( (2, 27.5) \) and \( (4, 30) \).
B: \( (30, 4) \) and \( (35, 8) \) — Neither of these points are correct; we found higher costs for these mileages.
C: \( (2, 2.5) \) and \( (4, 5) \) — Again, these are incorrect based on our calculations.
D: \( (4, 30) \) and \( (8, 35) \) — The first point is correct; we calculated \( (4, 30) \), but for \( m = 8 \): \[ C = 1.25(8) + 25 = 10 + 25 = 35 \] So, \( (8, 35) \) is also correct.
Thus, the points that appear on the graph of the linear function are found in option D: (4, 30) and (8, 35).