To determine which points would appear on the linear function given by the equation \(C = 1.25m + 25\), we can calculate the cost \(C\) for the specified mileages \(m\) in each of the options.
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For \(m = 2\): \[ C = 1.25(2) + 25 = 2.5 + 25 = 27.5 \] So the point is \((2, 27.5)\).
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For \(m = 4\): \[ C = 1.25(4) + 25 = 5 + 25 = 30 \] So the point is \((4, 30)\).
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For \(m = 30\): \[ C = 1.25(30) + 25 = 37.5 + 25 = 62.5 \] So the point is \((30, 62.5)\).
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For \(m = 35\): \[ C = 1.25(35) + 25 = 43.75 + 25 = 68.75 \] So the point is \((35, 68.75)\).
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For \(m = 8\): \[ C = 1.25(8) + 25 = 10 + 25 = 35 \] So the point is \((8, 35)\).
Based on those computations, let's analyze the points given in the options:
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Option A: \( \text{(2, 22.5)} \) and \( \text{(4, 20)} \)
- Both values computed were \( (2, 27.5) \) and \( (4, 30) \). This option does not match.
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Option B: \( \text{(30, 4)} \) and \( \text{(35, ?)} \)
- \( C(30) = 62.5 \), so \( (30, 4) \) does not match.
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Option C: \( \text{(4, 30)} \) and \( \text{(8, 35)} \)
- Both of these points match our calculations.
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Option D: \( \text{(2, 2.5)} \) and \( \text{(4, 5)} \)
- Both of these points do not match our calculations.
Therefore, the correct choice is: Option C: \( \text{(4, 30)} \) and \( \text{(8, 35)} \).