To determine which points from the options provided would appear on the plot of the linear function \( C = 1.25m + 25 \), we can substitute the values of \( m \) (miles driven) into the equation to find the corresponding \( C \) (total cost).
Let's evaluate each pair of points:
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For (2, 2.5): \[ C = 1.25(2) + 25 = 2.5 + 25 = 27.5 \] This point does not match (2, 2.5).
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For (4, 5): \[ C = 1.25(4) + 25 = 5 + 25 = 30 \] This point does not match (4, 5).
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For (30, 4): \[ C = 1.25(30) + 25 = 37.5 + 25 = 62.5 \] This point does not match (30, 4).
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For (35, 8): \[ C = 1.25(35) + 25 = 43.75 + 25 = 68.75 \] This point does not match (35, 8).
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For (2, 22.5): \[ C = 1.25(2) + 25 = 2.5 + 25 = 27.5 \] This point does not match (2, 22.5).
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For (4, 20): \[ C = 1.25(4) + 25 = 5 + 25 = 30 \] This point does not match (4, 20).
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For (4, 30): \[ C = 1.25(4) + 25 = 5 + 25 = 30 \] This point matches for \( m = 4 \).
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For (8, 35): \[ C = 1.25(8) + 25 = 10 + 25 = 35 \] This point matches for \( m = 8 \).
So the points that would appear based on the equation \( C = 1.25m + 25 \) are:
- (4, 30)
- (8, 35)
Thus, the answer from the options you provided is (4, 30) and (8, 35).