Refrigerators do not do work. Work has to be done UPON them to transfer heat out. I will assume that they meant to say 18 kJ of work IS CONSUMED by the refrigerator.
Refrigerator C.O.P. = Qout/Win
= 115/18 = 6.38
A refrigerator does 18kJ of work while moving 115 kJ of thermal enegy from inside the refrigerator. What is its coefficient of performance?
1 answer
1 answer