Volume of tub Vt=2*1*0.5=1m^3
Volume og pail Vp=r^2*pi/4=01^2*3.14159/4=
0.01*3.14159/4=0.007853975m^3
Vt/Vp=1/0.007853975=127.324062
127 pails
A rectangular tub with dimensions 2m x 1m x 0.5m is filled with water using a pail of radius 0.1 m and height 0.35 m. How many pails of water will be required? Give your answer to the nearest whole pail.
2 answers
Anonymus give the incorrect answer.
A=(r^2)*pi is Area of circle
Volume of right cylinder is:V=A*h
V=(r^2)*pi*h
So:
Volume of pail:
Vp=(0.1^2)*3.1415926535*0.35=
0.01*3.1415926535*0.35=
0.01099557428725m^3
Volume of tub Vt=2*1*0.5=1m^3
1/0.01099557428725=90.9456812
91 pails
A=(r^2)*pi is Area of circle
Volume of right cylinder is:V=A*h
V=(r^2)*pi*h
So:
Volume of pail:
Vp=(0.1^2)*3.1415926535*0.35=
0.01*3.1415926535*0.35=
0.01099557428725m^3
Volume of tub Vt=2*1*0.5=1m^3
1/0.01099557428725=90.9456812
91 pails