A rectangular tank 0.30m × 0.30m × 0.60 m is filled with ethyl alcohol to a full depth of 0.30 the pressure at the surface of the alcohol is 1.013x10⁶ Pa. The force exerted at the bottom

Answer 1

To find the force exerted at the bottom of the tank, we need to calculate the weight of the ethyl alcohol in the tank. We can use the formula:

Weight = Density x Volume x Gravity

Where:
- Density of ethyl alcohol = 789 kg/m³
- Volume of tank = 0.30m x 0.30m x 0.60m = 0.054 m³
- Gravity = 9.81 m/s²

Substituting these values into the formula, we get:

Weight = 789 kg/m³ x 0.054 m³ x 9.81 m/s²
Weight = 416.07 N

This is the weight of the ethyl alcohol in the tank. To find the force exerted at the bottom of the tank, we need to convert this weight to pressure using the formula:

Pressure = Force / Area

The area of the bottom of the tank is:

Area = Length x Width
Area = 0.30m x 0.30m
Area = 0.09 m²

Substituting the values we have:

Pressure = 416.07 N / 0.09 m²
Pressure = 4,623 N/m²

So the force exerted at the bottom of the tank is 4,623 N.