Let x be the border width.
The area of border tile is
A = (8+2x)(12+2x)- 8*12
which is (outer area) - (pool area)
= 4x^2 + 40x + 96 - 96
= 4x^2+ 40 x = 120
Solve for x.
You can simplify that to
x^2 + 10x - 30 = 0
Factor that for the one positive root.
A rectangular swimming pool is 8 meters long and 12 meters wide. A tile boarder of uniform width is to be built around the pool usinjg 120 square meters of tile. How wide should the boarder be? Round anser to the nearest hundredth.
3 answers
let the width of the border, note the spelling, be x m
then the whole pool area including the border is (8+2x)(12+2x) = 8(12) + 120
96 + 40x + 4x^2 = 216
x^2 + 10x -30 = 0
solve
I got x = 2.416 and some negative x number.
then the whole pool area including the border is (8+2x)(12+2x) = 8(12) + 120
96 + 40x + 4x^2 = 216
x^2 + 10x -30 = 0
solve
I got x = 2.416 and some negative x number.
your correct