p = perimeter = 3 L + 2 B
384 = L B so B = 384/L
p = 3 L + 768/L
dp/dL = 3 - 786 /L^2
= 0 for minimum
3 L^2 = 786
L^2 = 256
L = 16
B = 384/16 = 24
B/2 = 12
so two 12 by 16 areas
A rectangular study area is to be enclosed by a fence and divided into two equal parts, with a fence running along the division parallel to one of the sides. if the total area is 384 ft^2, find the dimensions of the study area that will minimize the total length of the fence. How much fence will be required?
1 answer
1 answer