a rectangular storage area is to be constructed along the sides of a tall building. A security fence is required along the three remaining sides of the area. What is the maximum area that can be enclosed with 1000m fencing?
4 answers
500x250
@ Steve I don't completely understand I want to knowhow we got to that answer/
well, draw a diagram. If the width is x, then the length is 1000-2x. So, the area is
a = x(1000-2x) = 1000x-2x^2
da/dx = 1000-4x
da/dx=0 when x=250
As is usual, you will find that for maximum area, the fencing is divided equally among the widths and lengths. In this case, that means 500 ft each.
2 widths of 250' each, and 1 length of 500.
Naturally, for a 4-sided enclosure, that just means a square.
a = x(1000-2x) = 1000x-2x^2
da/dx = 1000-4x
da/dx=0 when x=250
As is usual, you will find that for maximum area, the fencing is divided equally among the widths and lengths. In this case, that means 500 ft each.
2 widths of 250' each, and 1 length of 500.
Naturally, for a 4-sided enclosure, that just means a square.
Ok thanks I don't quite get it but I will follow your steps and Draw the diagram :)
0 answers