A rectangular piece of metal is 15in longer than it is wide. Squares with sides 3 in long are cut from four corners and the flaps are folded up to form an open box. If the volume is 1218in^3, what we’re the original deminsions of the piece of metal?
3 answers
Interesting. Are you able to visualize this? Any idea how to get started?
X^2+3x-1272=0
Needs to be factored
Needs to be factored
original piece is x by x+15
base of box = x-6 by x+9
height of box = 3
volume = 3(x-6)(x+9) = 1218
x^2 + 3x - 54 = 406
x^2 + 3x - 460 = 0
(x - 20)(x + 23) = 0
x = 20 or a negative
the original piece was 20 by 35 inches
base of box = x-6 by x+9
height of box = 3
volume = 3(x-6)(x+9) = 1218
x^2 + 3x - 54 = 406
x^2 + 3x - 460 = 0
(x - 20)(x + 23) = 0
x = 20 or a negative
the original piece was 20 by 35 inches
1 answer