The area is 80 x 65 = 5200
Path 1 is 2.5 times 80
Path 2 is 2.5 times 65
find these two areas and subtract from the 5200
A rectangular Park of length 80m and width 65m has two paths of uniform width 2.5m crossing each other. Find the area of remaining portion.
3 answers
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Length of rectangular park = 80 m
Breadth of rectangular park = 65 m
Uniform width of path = 2.5 m
Area of rectangular park = l x b = 80m x 65 m = 5200 sq.m.
Path 1 ( ABCD ) = 80 m
Path 2 ( EFGH ) = 65 m
AB = 2.5 m and AD = 80 m
EH = 2.5 m and EF = 65 m
KLMN which is the square between two cross-roads
KL = 2.5 m and KN = 2.5 m
Area of the path = Area of rectangle ABCD + Area of the rectangle EFGH - Area of the square KLMN
= AD x AB + EF x EH - KL x KN
= (80 x 2.5 + 65 x 2.5 - 2.5 x 2.5) sq.m.
= (200 + 162.5 - 6.25) sq.m.
= 356.25 sq.m.
Area of rectangular park - Area of roads = Area of the remaining portion of park
= 5200 sq.m. - 356.25 sq.m.
= 4,843.75 sq.m. is the area of remaining portion of the park.
Breadth of rectangular park = 65 m
Uniform width of path = 2.5 m
Area of rectangular park = l x b = 80m x 65 m = 5200 sq.m.
Path 1 ( ABCD ) = 80 m
Path 2 ( EFGH ) = 65 m
AB = 2.5 m and AD = 80 m
EH = 2.5 m and EF = 65 m
KLMN which is the square between two cross-roads
KL = 2.5 m and KN = 2.5 m
Area of the path = Area of rectangle ABCD + Area of the rectangle EFGH - Area of the square KLMN
= AD x AB + EF x EH - KL x KN
= (80 x 2.5 + 65 x 2.5 - 2.5 x 2.5) sq.m.
= (200 + 162.5 - 6.25) sq.m.
= 356.25 sq.m.
Area of rectangular park - Area of roads = Area of the remaining portion of park
= 5200 sq.m. - 356.25 sq.m.
= 4,843.75 sq.m. is the area of remaining portion of the park.