To find the width of the park, you can use the formula for the area of a rectangle, which is:
\[ \text{Area} = \text{Length} \times \text{Width} \]
You can rearrange this to find the width:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
Given the area \( A = 1.36 \times 10^8 \) ft² and the length \( L = 1.6 \times 10^4 \) ft, we can substitute these values into the equation for width:
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^4} \]
Now, perform the division:
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Divide the coefficients: \[ \frac{1.36}{1.6} = 0.85 \]
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Subtract the exponents of \(10\): \[ 10^8 \div 10^4 = 10^{8-4} = 10^4 \]
Putting it all together:
\[ \text{Width} = 0.85 \times 10^4 \text{ ft} \]
To express \(0.85 \times 10^4\) in standard form, you can convert it:
\[ 0.85 \times 10^4 = 8.5 \times 10^3 \text{ ft} \]
Thus, the width of the park is:
\[ \text{Width} = 8.5 \times 10^3 \text{ ft} \]