To find the width of the park, we can use the formula for the area of a rectangle, which is:
\[ \text{Area} = \text{Length} \times \text{Width} \]
We can rearrange this to find the width:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
Given the area is \(1.36 \times 10^8 , \text{ft}^2\) and the length is \(1.6 \times 10^4 , \text{ft}\):
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^4} \]
Now, let's divide the numerical coefficients and subtract the exponents:
- Divide the coefficients:
\[ \frac{1.36}{1.6} = 0.85 \]
- Subtract the exponents:
\[ 10^{8 - 4} = 10^4 \]
Putting it all together:
\[ \text{Width} = 0.85 \times 10^4 \]
To express \(0.85\) in scientific notation:
\[ 0.85 = 8.5 \times 10^{-1} \]
So:
\[ \text{Width} = 8.5 \times 10^{-1} \times 10^4 = 8.5 \times 10^{3} \]
Thus, the width of the park is:
\[ \text{Width} = 8.5 \times 10^3 , \text{ft} \]
The correct response is:
8.5×10³ ft.