To find the width of the park, divide the area by the length.
Given:
- Area = \(1.36 \times 10^8\) ft²
- Length = \(1.6 \times 10^4\) ft
The formula for the width \(w\) is:
\[ w = \frac{\text{Area}}{\text{Length}} = \frac{1.36 \times 10^8}{1.6 \times 10^4} \]
Now, we can divide the coefficients and subtract the exponents:
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Divide the coefficients: \[ \frac{1.36}{1.6} = 0.85 \]
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Subtract the exponents: \[ 10^8 \div 10^4 = 10^{8 - 4} = 10^4 \]
Combining these results gives:
\[ w = 0.85 \times 10^4 \]
To express \(0.85\) in scientific notation: \[ 0.85 = 8.5 \times 10^{-1} \]
Thus, \[ w = 8.5 \times 10^{-1} \times 10^4 = 8.5 \times 10^{4 - 1} = 8.5 \times 10^3 \text{ ft} \]
Therefore, the width of the park is: \(\boxed{8.5 \times 10^3 \text{ ft}}\)
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