A rectangular parcel of land has an area of 4,000 ft2. A diagonal between opposite corners is measured to be 10 ft longer than one side of the parcel. What are the dimensions of the land, correct to the nearest foot?

Answer 1

if the side is x, then the other side is 4000/x. So, we have

x^2 + (4000/x)^2 = (x+10)^2
x ≈ 91

check:
the rectangle is about 91x44
The diagonal is 101 = 91+10