A rectangular lawn 80m *60m has two rmads each 10m wide running in the middle of it, one parallel to the length and the other parallel to the breadth. Find the cost of gravelling them at ₹1.20 square metre.
4 answers
Now I showed you how to do one by subtracting rectangles. You do this one.
area of long strip = 80*10 or 800 m^2
area of shorter strip = 60(10) = 600 m^2
total = 1400 m^2
BUT, we counted the intersection twice
so we subtract 10(10) or 100 m^2
are of the two "rmads" is 1300 m^2
cost = 1.2(1300)
= 1560 units of money
area of shorter strip = 60(10) = 600 m^2
total = 1400 m^2
BUT, we counted the intersection twice
so we subtract 10(10) or 100 m^2
are of the two "rmads" is 1300 m^2
cost = 1.2(1300)
= 1560 units of money
answer is 1560
area of road that is parallel to lengh
= 80x10= 800 sq m
area of road that is parallel to breadth = 60 x 10 = 600 sq m
Area of two road = (800+600-100)
=1300 sq m
cost at 1 sq m = 1.20
cost at 1300 sq m = 1.2 x 1300
= RS.1560
thanks you !!!
= 80x10= 800 sq m
area of road that is parallel to breadth = 60 x 10 = 600 sq m
Area of two road = (800+600-100)
=1300 sq m
cost at 1 sq m = 1.20
cost at 1300 sq m = 1.2 x 1300
= RS.1560
thanks you !!!
1 answer