12a^2-5a-2m^2
= (3a -2m)(4a + m)
If we add 1 m to the end of each length and width
area of garden including path
= (3a-2m+2)(4a+m+2)
So area of path
= (3a-2m+2)(4a+m+2) - (3a -2m)(4a + m)
I will let you do the expanding and simplifying
sub in a = 6 into your answer for the path which will still contain the variable m
volume of concrete
= .1(answer you have above) m^3
A rectangular garden has an area if
12a^2-5a-2m^2
A.) Write the area as the product of two binomials with integer coefficients
B.) the garden is to be completely enclosed by a path 1 m wide. find and simplify an expression for the area of the path
C.) the path is concrete, poured to a depth of 10 cm. calculate the volume in m^3 of concrete used if a=6
PLEASE help:) thanks:)
1 answer