We can use the Pythagorean theorem to solve this problem. Let's label one of the corners as A, the opposite corner as C, and the third corner (adjacent to both A and C) as B. Then, we have:
AB = 64 meters (since sides AB and CD are parallel and equal in length)
BC = 100 meters (since sides BC and AD are parallel and equal in length)
AC = ? (what we're trying to find)
Using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides, we have:
AC² = AB² + BC²
AC² = 64² + 100²
AC² = 4096 + 10000
AC² = 14096
AC ≈ √14096
AC ≈ 118.7 meters (rounded to the nearest meter)
Therefore, the player ran approximately 119 meters.
A rectangular football field is 64 meters wide and 100 meters long. A player runs from one corner of the field in a diagonal line to the opposite corner.
How far did the player run?
Round your answer to the nearest meter.
1 answer
1 answer