A rectangular field has a perimeter of 442m. If the length and the width are in ratio 12:5 find the diagonal and 2 area of the rectangular field

2 answers

L / W = 12 / 5 Multiply both sides by 5

5 L / W = 12 Multiply both sides by W

5 L = 12 W Divide both sides by 5

L = ( 12 / 5 ) W

L = 2.4 W

P = 2 W + 2 L =

2 ( W + L ) = 442 Divide both sides by 2

W * L = 221

W + 2.4 W = 221

3.4 W = 221 Divide both sides by 3.4

W = 221 / 3.4

W = 65 m

L = 2.4 W

L = 2.4 * 65 = 156 m

d = sqrt ( L ^ 2 + W ^ 2 )

d = sqrt ( 156 ^ 2 + 65 ^ 2 )

d = sqrt ( 24336 + 4225 )

d = sqrt ( 28561 )

d = 169 m

A = W * L = 65 * 156 = 10,140 m ^ 2
P = 2 W + 2 L =

2 ( W + L ) = 442 Divide both sides by 2

W + L = 221