if the cardboard has height x and width y,
a = xy
printed area is (x-6)(y-4) = 150
so, we want to minimize xy.
a = xy = x(150/(x-6) + 4)
da/dx = 4(x^2-12x-189)/(x-6)^2
since the denominator is never zero, da/dx=0 when
x^2 - 12x - 189 = 0
(x+9)(x-21) = 0
so, x = 21
y = 14
area of poster is 294
area of printing is 15x10 = 150
A rectangular cardboard poser is to have 150 sq ft in for printed matter. It is to have a 3inch margin at the top and bottom and a 2inch margin at the right and left. Find the dimensions of the poser so that the amount of cardboard used is minimized.
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