A rectangular box is 4cm wide, 4cm tall, and 10cm long. What is the diameter of the smallest circular opening through which the box will fit? Round to the nearest tenth of a centimeter. Is it 4 squared plus 4 squared which equals 32 then take the square root of 32 and get 5.65 or 5.7.

Answer 1

Sliding the box through the circle length wise means that the circle must be able to at least as long as the diagonal.

So you are right,
D^2 = 4^2 + 4^2 = 32
D = √32 = appr 5.7