you want dv/dt, where
v = x^2 h
The good old product rule says that
dv/dt = 2xh dx/dt + x^2 dh/dt
You have all the stuff you need, so just plug it in and watch the fun!
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x^2h cm^3. Find the rate at which the volume of the box is changing when the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.
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