a rectangle with side of 6 cm and 5 cm has the same area as an isoceles triangle with base length 12 cm.find the altitude to the base of the triangle and side of the triangle
2 answers
the height of two tower are 40 feet and 10 feet.if they are 16 feet apart find the distance between their tops
for the triangle,
6*5 = 1/2 * 12 * h
Now, knowing h, the side length s can be found using
s^2 = 6^2 + h^2
For the towers, the distance z is
z^2 = 16^2 + (40-10)^2
6*5 = 1/2 * 12 * h
Now, knowing h, the side length s can be found using
s^2 = 6^2 + h^2
For the towers, the distance z is
z^2 = 16^2 + (40-10)^2