A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=11-x^2. What are the dimensions of such a rectangle with the greatest possible area?
Width=? Height=?
Area= height*width=y(2x)
Area=(11-x^2)(2x)
solve for dArea/dx, set to zero, solve for x. Width will be 2x, height y.
ty very much!