To determine if the four points form a rectangle and to calculate its area, we start by considering the given vertices: \( (0,0) \), \( (2,2) \), \( (9,-4) \), and \( (7,-6) \).
First, let's find the distances between all pairs of points using the distance formula \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \).
Calculating the distances:
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Distance between (0,0) and (2,2): \[ d_1 = \sqrt{(2 - 0)^2 + (2 - 0)^2} = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} \approx 2.83 \]
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Distance between (0,0) and (9,-4): \[ d_2 = \sqrt{(9 - 0)^2 + (-4 - 0)^2} = \sqrt{9^2 + (-4)^2} = \sqrt{81 + 16} = \sqrt{97} \approx 9.85 \]
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Distance between (0,0) and (7,-6): \[ d_3 = \sqrt{(7 - 0)^2 + (-6 - 0)^2} = \sqrt{7^2 + (-6)^2} = \sqrt{49 + 36} = \sqrt{85} \approx 9.22 \]
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Distance between (2,2) and (9,-4): \[ d_4 = \sqrt{(9 - 2)^2 + (-4 - 2)^2} = \sqrt{(7)^2 + (-6)^2} = \sqrt{49 + 36} = \sqrt{85} \approx 9.22 \]
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Distance between (2,2) and (7,-6): \[ d_5 = \sqrt{(7 - 2)^2 + (-6 - 2)^2} = \sqrt{(5)^2 + (-8)^2} = \sqrt{25 + 64} = \sqrt{89} \approx 9.43 \]
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Distance between (9,-4) and (7,-6): \[ d_6 = \sqrt{(7 - 9)^2 + (-6 + 4)^2} = \sqrt{(-2)^2 + (-2)^2} = \sqrt{4 + 4} = \sqrt{8} \approx 2.83 \]
From our calculations, we see that:
- \( d_1 \approx 2.83 \) (from (0,0) to (2,2))
- \( d_6 \approx 2.83 \) (from (9,-4) to (7,-6))
- \( d_2 \approx 9.85 \) (from (0,0) to (9,-4))
- \( d_4 \approx 9.22 \) (from (2,2) to (9,-4))
To find the area of a rectangle, we use the formula for the area: \[ \text{Area} = \text{base} \times \text{height} \]
Let’s verify if the distances can give us two pairs that are equal. Given our pairings, we have two longer sides \( \sqrt{85} \) (sides across from each other) and two shorter sides \( \sqrt{8} \) for both diagonals.
Now, if we could take one of the pairings:
- Base can be taken as \( \sqrt{85} \)
- Height can be taken as \( \sqrt{8} \)
Thus, the area \( A \) can be calculated as follows: Area = length × width = \( \sqrt{85} \) and \( \sqrt{8} \).
Calculating the area of the rectangle \( A \): \[ A \approx 9.22 \text{ (can represent the longer side)} \cdot 2.83 \text{ (shorter)} = 26.14. \]
Thus, the area of the rectangle is approximately \( \textbf{26.14} \).