Draw a diagram. The area is
A = xy = -x lnx
dA/dt = -lnx - 1
A has a max of 1/e when x = 1/e
A rectangle is drawn in the first quadrant so that it has two adjacent sides on the coordinate axes and one
vertex on the curve y = − ln x. Find the x-coordinate of the vertex for which the area of the rectangle is a
maximum.
1 answer