P = 2L + 2W
68 = (2 * 23) + (2 * 11)
A rectangle is 12in longer than it is wide. The perimeter is 68m. Write an equation and show steps to find its length and width.
I need help figuring out what the equation would be. I found out that the length is 23 in and the width is 11 in, but I can't figure out how to make it into an equation.
4 answers
A rectangle is 12 in longer than it is wide mean:
L = W +12
Perimeter:
P = 2 L + 2 W = 2 ( L + W ) = 2 ( W + 12 + W ) = 2 ∙ ( 2 W + 12 )
P = 4 W + 24
68 = 4 W + 24
Subtract 24 to both sides
68 - 24 = 4 W + 24 - 24
44 = 4 W
Divide both sides by 4
44 / 4 = W
11 = W
W = 11 in
L = W +12 = 11 + 12 = 23 in
L = W +12
Perimeter:
P = 2 L + 2 W = 2 ( L + W ) = 2 ( W + 12 + W ) = 2 ∙ ( 2 W + 12 )
P = 4 W + 24
68 = 4 W + 24
Subtract 24 to both sides
68 - 24 = 4 W + 24 - 24
44 = 4 W
Divide both sides by 4
44 / 4 = W
11 = W
W = 11 in
L = W +12 = 11 + 12 = 23 in
I also need to incorporate that the length is 12 more than the width into the equation, though.
Thank you Bosnian
1 answer