A rectangle is 12 cm longer than it is wide. a wooden walk 2 ft wide is placed around the pond. the area covered by the pond and walk is 160 ft^2 greater than the area covered by the pond alone. What are the dimensions of the pond

Answer 1

I suspect that the pond is 12 ft longer than it is wide. 12 cm is a ridiculous amount. Assuming that, we have the dimensions of w and w+12.

Then we are told that

(w+4)(w+12+4) - (w)(w+12) = 160
Solve that and you find w=12.

So, the pond is 12x24

16*28 - 12*24 = 160