A rectangle has area 6 cm (squared) and diagonal of length 2√5 cm. What is its perimeter?

Question

thanks

Answer 1

let the width be x and the length be y

we know xy = 6 and
x^2 + y^2 = (2√5)^2 = 20

Perimeter = 2(x+y)

from algebra we know
(x+y)^2 = x^ + 2xy + y^2
but we know the values on the right side,
so
(x+y)^2 = 20 + 6 = 26
then x+y = √26
and the perimeter is 2√26

Answer 2

let the width be x and the length be y

we know xy = 6 and
x^2 + y^2 = (2�ã5)^2 = 20

Perimeter = 2(x+y)

from algebra we know
(x+y)^2 = x^ + 2xy + y^2
but we know the values on the right side,
so
(x+y)^2 = 20 +12=32
then x+y = �ã32
and the perimeter is 2�ã32

Answer 3

Why is math so hard?