W = 8
L = 16
x^2 = w^2 + L^2
x^2 = 8^2 + 16^2 = (2^3)^2 + (2^4)^2
x^2 = 2^6 + 2^8
x^2 = 2^6 + 4*2^6
x^2 = 5 * 2^6
x^2 = sqrt 5 * 2^3
x = 8 sqrt 5
A rectangle has a width of 8 meters. The length is twice as long as the width. What is the length of the diagonal? Show your work
2 answers
The diagonal is c.
a^2 + b^2 = c^2
8^2 + 16^2 = c^2
64 + 256 = c^2
320 = c^2
17.889 = c
a^2 + b^2 = c^2
8^2 + 16^2 = c^2
64 + 256 = c^2
320 = c^2
17.889 = c