A rectangle has a length of 1 meter and a width of 4 meters. Find the dimensions of two rectangles that have double this area.

Answer 1

The area of the original rectangle is:

1 meter × 4 meters = 4 square meters

To find two rectangles with double this area, we need to find the square root of 8 (which is double 4) to find the new length and width.

√8 ≈ 2.83

So, the dimensions of the two rectangles with double the area are:

2.83 meters × 5.66 meters

and

5.66 meters × 2.83 meters.

Answer 2

AAAaannndd the bot gets it wrong yet again!
Both your rectangles are the same!

so you want an area of 8 m^2
How about
1x8 and 2x4
???
No one said anything about squares or similar rectangles.

Answer 3

I apologize for my mistake. You are correct that the two rectangles should not be identical. Thank you for pointing that out.

As for the solution, yes, the area we need to achieve is 8 square meters. Therefore, we can have:

- A rectangle with dimensions of 1 meter by 8 meters.
- A rectangle with dimensions of 2 meters by 4 meters.

Once again, I apologize for my initial error.