To determine how many times Charlie needs to fill the 1/3-cup measuring cup to measure out 3 1/3 cups of flour, we can set up the equation like this:
Initial Problem:
\[ 3 \frac{1}{3} \div \frac{1}{3} \]
Solution:
First, let's convert the mixed number \(3 \frac{1}{3}\) into an improper fraction:
\[ 3 \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{9 + 1}{3} = \frac{10}{3} \]
Now we need to divide \(\frac{10}{3}\) by \(\frac{1}{3}\):
\[ \frac{10}{3} \div \frac{1}{3} \]
Dividing by a fraction is the same as multiplying by its reciprocal, so we have:
\[ \frac{10}{3} \times \frac{3}{1} = \frac{10 \times 3}{3 \times 1} = \frac{30}{3} = 10 \]
Thus, the final equation is:
\[ 3 \frac{1}{3} \div \frac{1}{3} = 10 \]
Conclusion:
Charlie will need to fill the 1/3-cup measuring cup 10 times.
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