n = N e^kt
2 = 1 e^(k*8)
ln 2 = 8 k = .693
k = .0866
dn/dt = kN e^kt
at t = 0
dn/dt = k N = .0866 N
You must know how many there are now, N, to say how many per month are added.
A recent study shows that the number of Australian homes with a computer doubles every 8 months. Assuming that the number is increasing continuously, at approximately what monthly rate must the number of Australian computer owners be increasing for this to be true?
1 answer