A reaction of 56.7 of Na and 39.3 g of Br2 yields 47.0 of NaBr. What is the percent yield?

Answer 1

This is a limiting reagent (LR) problem.
..................2Na + Br2 ==> 2NaBr
mols Na = 56.6/atomic mass Na = ?
mols Br2 = 39.3/molar mass Br2 = ?

Convert mols Na to mols NaBr produced knowing that 2 mol Na will produce 2 mols NaBr.
Do the same to convert mols Br2 to mols NaBr produced knowing that 1 mol Br2 will produce 2 mols NaBr

In LR problems, the SMALLEST number of mols NaBr produced is the correct shoice and the LR is the reactant that gives the smallest number of mols product formed.

Using the smallest number of mols NaBr produced, convert to grams NaBr. That is the theoretical yield (TY). The actual yield (AY) is given in the problem.
% yield = (AY/TY)*100 =
Post your work if you run into trouble.

Answer 2

I posted the above response.