Sarah, do you know how to calculate the amount of NaBr formed (this is a limiting reagent problem). If you do,that calculation gives you the amount of NaBr under 100% yield.
% yield = 100(actual yield/1--% yield)
A reaction of 48.5 g of Na and 53.7 g of Br2 yields 55.4 g of NaBr. What is the percent yield?
2Na(s)+Br2(g)--->2NaBr(s)
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